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Proof step 2 from proof nls-mult-div (previous step)

i < (i * i1) / j, i1 < j, 0 ≤ i, 0 < (i * i1) / j, 0 < j ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 3:
i = 0, i < (i * i1) / j, i1 < j, 0 ≤ i, 0 < (i * i1) / j, 0 < j ⊦
Proof step 6:
i < (i * i1) / j, i1 < j, 0 ≤ i, 0 < (i * i1) / j, 0 < j ⊦ i = 0

Rule argument

fma: i = 0

Additional information

Used formulas: i = 0