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Proof step 6 from proof nls-mult-div (previous step)

i < (i * i1) / j, i1 < j, 0 ≤ i, 0 < (i * i1) / j, 0 < j ⊦ i = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
0 < j, i < (i * i1) / j, i1 < j, 1 < (i * i1) / j, 0 < (i * i1) / j, 0 < i ⊦ i = 0

Rule argument

Additional information

Used simplifier rules: forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%lels-02: ⊦ i ≠ j → (i ≤ j ↔ i < j); from specification int-abs