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Proof step 10 from proof divides-abs-02 (previous step)

i * i0 = abs(j) * j0 ⊦ i * i0 = j * j0, i0 * i + j * j0 = 0

User applied rule insert equation

And obtained the following new goals

Proof step 11:
i * i0 = abs(j) * j0 ⊦ abs(j) * j0 = j * j0, abs(j) * j0 + j * j0 = 0

Rule argument

pos: left 1 flags:

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i; from specification int-mult