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Proof step 9 from proof divides-abs-02 (previous step)

i * i0 = abs(j) * j0 ⊦ i * i0 = j * j0, i * ~ i0 = j * j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
i * i0 = abs(j) * j0 ⊦ i * i0 = j * j0, i0 * i + j * j0 = 0

Rule argument

Additional information

Used simplifier rules: negeq: ⊦ ~ i = j ↔ i + j = 0; from specification int-abs%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%minus-left: ⊦ ~ i * j = ~(i * j); from specification int-mult