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Proof step 12 from proof divides-prime (previous step)

0 < i * i0, 0 ≤ i * i0, 2 ≤ i * i0, i0 < i * i0, i0 ≤ 1, ∀ i1. 1 < i1 ∧ i1 < i * i0 → ¬ i1 | i * i0 ⊦ abs(i) = 1, abs(i) = i * i0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 13:
⊦ i * j = j * i
Proof step 14:
0 < i0 * i, 0 ≤ i0 * i, 2 ≤ i0 * i, i0 < i0 * i, i0 ≤ 1, ∀ i1. 1 < i1 ∧ i1 < i0 * i → ¬ i1 | i0 * i ⊦ abs(i) = 1, abs(i) = i0 * i

Rule argument

spec: int-mult inst: name: commutativity seq: ⊦ i * j = j * i subst: [j, i] → [i0, i] flags: rewrite

Additional information

Used terms: i0, i