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Theorem divides-prime
⊦ prime(j) → (i | j ↔ abs(i) = j ∨ abs(i) = 1)
Type: A user defined theorem
Validity: The proof is valid.
Features: simp, localsimp,
Comment:
Used by:
gcd-one-prime
,
gcd-primes
,
max_prime_divisor-divides-03
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 10
Proof steps: 20
Used lemmas:
div-one
,
divides-mone
,
div-abs-03
,
divides-neg
,
div-mult
,
divides
,
prime-def
,
Used spec theorems:
int-mult
/
commutativity
int-mult
/
ls-same-01
int-abs
/
Abs-pos
Used simplifier rules:
int-abs
/
forward-le-05
int-abs
/
abs-16
int-mult
/
le-same
int-abs
/
forward-lele
int-abs
/
forward-le-01
int-abs
/
forward-le
int-abs
/
abs
int-mult
/
eq-same
int-mult
/
zero-gr
int-mult
/
zero-ge
int-abs
/
bet
int-abs
/
numleledel
int-abs
/
zero-gels-01
int-abs
/
lsone
int-mult
/
ls-same-03
int-abs
/
lels-02
int-mult
/
zero-ge-01
int-mult
/
zero-eq
int-mult
/
zero-gr-03
int-abs
/
neg-13
int-mult
/
succ-rmerge
int-mult
/
associativity
int-mult
/
commutativity
int-mult
/
zero-gr-01
int-abs
/
numls-03
int-abs
/
lels
int-abs
/
mone-08
int-abs
/
neg-07
int-abs
/
forward-le-02
int-basic2
/
add-c
int-basic2
/
add-a
int-abs
/
numadd-01
int-abs
/
negeq
int-abs
/
abs-08