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Proof step 10 from proof gcd-mult (previous step)

⊦ j = 0, i = 0, i1 = 0, gcd(abs(i) * abs(i1), abs(j) * abs(i1)) = gcd(abs(i), abs(j)) * abs(i1)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-gcd inst: name: gcd-mult-pos seq: ⊦ 0 < i1 ∧ 0 < i ∧ 0 ≤ j → gcd(i * i1, j * i1) = gcd(i, j) * i1 subst: [j, i1, i] → [abs(j), abs(i1), abs(i)] flags: rewrite, current

Additional information

Used simplifier rules: abs-06: ⊦ 0 < abs(i) ↔ i ≠ 0; from specification int-abs%abs-03: ⊦ 0 ≤ abs(i); from specification int-abs Used terms: abs(j), abs(i1), abs(i)