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Theorem gcd-mult

⊦ gcd(i * i1, j * i1) = gcd(i, j) * abs(i1)

Type: A user defined theorem
Validity: The proof is valid.
Features: simp, localsimp,
Comment:
Used by: gcd-max-prop, gcd-mult-pos-01, square-neq-any-pos-02, square-neq-pos-h,
Used by units in proved state:
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 6
Proof steps: 8
Used lemmas: gcd-mult-pos, gcd-abs-rew-02, gcd-zero-03, gcd-com, gcd-zero-04, gcd-zero,
Used spec theorems:
- Used simplifier rules: