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Theorem abs-eqall
⊦ abs(i * j) = abs(i) * abs(j)
Type: A user defined theorem
Validity: The proof is valid.
Features: simp, localsimp,
Comment:
Used by:
modzero-08
,
square-abs
,
square-eq
,
square-le-02
,
square-ls
,
Used by units in proved state:
int-gcd
,
int-div
,
int-square
,
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 3
Proof steps: 5
Used lemmas:
zero-ge-02
,
zero-le-01
,
zero-ge-01
,
commutativity
,
associativity
,
minus-left
,
Used spec theorems:
Used simplifier rules:
int-abs
/
forward-le-02
int-abs
/
lels-01
int-abs
/
neg-15
int-abs
/
sub-eq
int-basic2
/
add-zero-rev
int-abs
/
zero-gels-03
int-abs
/
forward-le-01
int-abs
/
Abs-pos
int-abs
/
abs-18
int-abs
/
lels-02
int-abs
/
lels
int-abs
/
abs-08
int-abs
/
negeq
int-abs
/
abseq
int-abs
/
zero-gels-04
int-basic2
/
add-a
int-basic2
/
add-c