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Theorem gcd-abs-rew-02

⊦ gcd(i, j) = gcd(abs(i), abs(j))

Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by: gcd-abs-rew, gcd-abs-rew-01, gcd-div-gcd, gcd-divides-both, gcd-mult, gcd-neg, gcd-nls, gcd-rec, gcd-rec-sub-01, gcd-rec-sub-03, gcd-same, gcd-zero-04, gcdex,
Used by units in proved state:
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 11
Proof steps: 19
Used lemmas: div-abs-02, gcd-zero, gcd-div2, gcd-div1, div-abs-01, gcd-max,
Used spec theorems:
- int-basic1/lst-01
Used simplifier rules: