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Theorem gcd-rec
⊦ j ≠ 0 → gcd(i, j) = gcd(abs(j), abs(i) % abs(j))
Type: A user defined theorem
Validity: The proof is valid.
Features:
Comment:
Used by:
gcd-mult-01
,
gcd-mult-pos
,
gcd-rec-pos
,
gcdhex
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 27
Proof steps: 41
Used lemmas:
div-mult
,
divides-mult-sub
,
divides
,
gcd-div2
,
gcd-div1
,
gcd-nls-01
,
gcd-com
,
gcd-zero-04
,
gcd-less
,
gcd-abs-rew-02
,
Used spec theorems:
int-basic1
/
lst-01
int-mult
/
commutativity
Used simplifier rules:
int-div
/
div-elim-pospos
int-abs
/
forward-le-05
int-abs
/
forward-le-01
int-abs
/
abs-03
int-abs
/
abs-06
int-abs
/
abs-01
int-basic1
/
lf-02
int-mult
/
eq-dist
int-basic2
/
add-a
int-basic1
/
ls-01
int-abs
/
lels-03
int-abs
/
abs-07
int-abs
/
sub-eq
int-basic2
/
add-c
int-mult
/
associativity
int-mult
/
commutativity