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Theorem gcd-div-gcd
⊦ i ≠ 0 → gcd(i / gcd(i, j), j / gcd(i, j)) = 1
Type: A user defined theorem
Validity: The proof is valid.
Features: simp, localsimp,
Comment: i / gcd(i,j) is the 'other' factor of i besides the gcd, analogous j / gcd(i, j). If those two would have a common divisor, it had to be part of the gcd of i and j, so their gcd is 1
Used by:
square-neq-any-pos-01
,
square-neq-any-pos-02
,
square-neq-pos
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 4
Proof steps: 5
Used lemmas:
gcd-abs
,
gcd-zero-zero
,
gcd-zero-04
,
gcd-zero-03
,
gcd-div-gcd-pos
,
gcd-abs-rew-02
,
Used spec theorems:
Used simplifier rules:
int-abs
/
abs-06
int-abs
/
abs-01
int-abs
/
abs-07
int-div
/
zero
int-div
/
abs-01
int-div
/
div-same
int-div
/
abs