[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Theorem gcd-abs
⊦ abs(gcd(i, j)) = gcd(i, j)
Type: A user defined theorem
Validity: The proof is valid.
Features: simp, localsimp,
Comment:
Used by:
div-gcd-zero
,
gcd-div-gcd
,
gcd-div-rest
,
square-neq-any-pos-02
,
square-neq-pos-h
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 0
Proof steps: 1
Used lemmas:
gcd-zero-02
,
Used spec theorems:
Used simplifier rules:
int-abs
/
lels-01
int-abs
/
abs-18