[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Theorem gcd-div-gcd-pos
0 < i, 0 < j ⊦ gcd(i / gcd(i, j), j / gcd(i, j)) = 1
Type: A user defined theorem
Validity: The proof is valid.
Features: simp, localsimp,
Comment: i / gcd(i,j) is the 'other' factor of i besides the gcd, analogous j / gcd(i, j). If those two would have a common divisor, it had to be part of the gcd of i and j, so their gcd is 1
Used by:
gcd-div-gcd
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 13
Proof steps: 22
Used lemmas:
gcd-zero
,
div-mult
,
gcd-zero-04
,
gcd-max
,
divides
,
gcd-com
,
gcd-div-rest
,
gcd-zero-zero
,
gcd-less-eq-zero
,
gcd-one
,
Used spec theorems:
Used simplifier rules:
int-basic1
/
forward-pos
int-abs
/
gr-def
int-abs
/
absle
int-abs
/
lels
int-abs
/
lels-03
int-abs
/
lels-01
int-basic1
/
ls-01
int-div
/
div-elim-pospos
int-abs
/
forward-le-05
int-abs
/
forward-le-01
int-mult
/
zero-ge
int-mult
/
zero-gr
int-mult
/
le-same
int-abs
/
bet
int-basic1
/
lf-02
int-mult
/
zero-left
int-abs
/
lels-02
int-mult
/
zero-neq-01
int-mult
/
one-01
int-mult
/
eq-one
int-mult
/
eq-same-02
int-abs
/
abs-16
int-mult
/
commutativity
int-mult
/
associativity