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Proof step 3 from proof gcd-neg (previous step)

⊦ gcd(abs(~ i), abs(j)) = gcd(i, j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ gcd(abs(i), abs(j)) = gcd(i, j)

Rule argument

Additional information

Used simplifier rules: abs-neg: ⊦ abs(~ i) = abs(i); from specification int-abs