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Proof step 4 from proof gcd-neg (previous step)

⊦ gcd(abs(i), abs(j)) = gcd(i, j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ gcd(i, j) = gcd(abs(i), abs(j))
Proof step 6:
⊦ gcd(abs(abs(i)), abs(abs(j))) = gcd(i, j)

Rule argument

spec: int-gcd inst: name: gcd-abs-rew-02 seq: ⊦ gcd(i, j) = gcd(abs(i), abs(j)) subst: [j, i] → [abs(j), abs(i)] flags: rewrite, current

Additional information

Used terms: abs(j), abs(i)