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Theorem gcd-one-eq-01

⊦ i ≠ 0 → (abs(i) / gcd(i, j) = 1 ↔ gcd(i, j) = abs(i))

Type: A user defined theorem
Validity: The proof is valid.
Features: simp, localsimp,
Comment:
Used by:
Used by units in proved state:
Proof exists?: Yes

View the proof

Infos about the proof

Proved?: Yes
Interactions: 3
Proof steps: 3
Used lemmas: gcd-zero-zero, gcd-com, gcd-abs-rew, gcd-one-eq,
Used spec theorems:
- Used simplifier rules:
  - int-div/div-same