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Proof step 5 from proof gcd-primes (previous step)

i0 | i, i0 | j, prime(i), prime(j), 0 < i0, 1 < i0 ⊦ i = j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ prime(j) → (i | j ↔ abs(i) = j ∨ abs(i) = 1)
Proof step 7:
prime(j), i0 | i, abs(i0) = j ∨ abs(i0) = 1, prime(i), prime(j), 0 < i0, 1 < i0 ⊦ i = j

Rule argument

spec: int-gcd inst: name: divides-prime seq: ⊦ prime(j) → (i | j ↔ abs(i) = j ∨ abs(i) = 1) subst: [j, i] → [j, i0] flags: rewrite, current

Additional information

Used terms: j, i0