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Proof step 7 from proof gcd-primes (previous step)

prime(j), i0 | i, abs(i0) = j ∨ abs(i0) = 1, prime(i), prime(j), 0 < i0, 1 < i0 ⊦ i = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
j | i, prime(i), prime(j), 1 < j, 0 < j ⊦ j = 1, i = j

Rule argument

Additional information

Used simplifier rules: div-one: ⊦ 1 | i;%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1%lf-02: ⊦ i < j ∧ j = i0 → i < i0; (forward) from specification int-basic1%abs-16: ⊦ 0 < j → abs(j) = j; from specification int-abs