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Proof step 8 from proof gcd-primes (previous step)

j | i, prime(i), prime(j), 1 < j, 0 < j ⊦ j = 1, i = j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ prime(j) → (i | j ↔ abs(i) = j ∨ abs(i) = 1)

Rule argument

spec: int-gcd inst: name: divides-prime seq: ⊦ prime(j) → (i | j ↔ abs(i) = j ∨ abs(i) = 1) subst: [j, i] → [i, j] flags: rewrite, current

Additional information

Used simplifier rules: abs-16: ⊦ 0 < j → abs(j) = j; from specification int-abs Used terms: i, j