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Proof step 6 from proof gcd-rec-sub-03 (previous step)

⊦ gcd(i, i0 + i) = gcd(i0 + i, i0), 0 < i ∧ i < i0 + i

User applied rule cut formula

And obtained the following new goals

Proof step 7:
i < 0 ⊦ gcd(i, i0 + i) = gcd(i0 + i, i0), 0 < i ∧ i < i0 + i
Proof step 51:
⊦ i < 0, gcd(i, i0 + i) = gcd(i0 + i, i0), 0 < i ∧ i < i0 + i

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0