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Proof step 7 from proof gcd-rec-sub-03 (previous step)

i < 0 ⊦ gcd(i, i0 + i) = gcd(i0 + i, i0), 0 < i ∧ i < i0 + i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
i < 0 ⊦ gcd(i, i0 + i) = gcd(i0 + i, i0), 0 < i ∧ i < i0 + i

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs