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Proof step 41 from proof gcd-rec (previous step)

abs(i) = i0 * abs(j) + j0, gcd(abs(j), j0) < gcd(abs(i), abs(j)), 0 ≤ i0, 0 ≤ j0, j0 < abs(j) ⊦ j = 0, true ∧ gcd(abs(i), abs(j)) | j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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