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Proof step 1 from proof gcdex (conclusion)
⊦ ∃ i0, j0. gcd(i, j) = i * i0 + j * j0
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 2
:
⊦ gcd(i, j) = gcd(abs(i), abs(j))
Proof step 3
:
⊦ ∃ i0, j0. gcd(abs(i), abs(j)) = i * i0 + j * j0
Rule argument
spec: int-gcd inst: name: gcd-abs-rew-02 seq: ⊦ gcd(i, j) = gcd(abs(i), abs(j)) subst: [j, i] → [j, i] flags: rewrite, current
Additional information
Used terms: j, i