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Proof step 3 from proof gcdex (previous step)

⊦ ∃ i0, j0. gcd(abs(i), abs(j)) = i * i0 + j * j0

User applied rule cut formula

And obtained the following new goals

Proof step 4:
abs(i) < abs(j) ⊦ ∃ i0, j0. gcd(abs(i), abs(j)) = i * i0 + j * j0
Proof step 14:
⊦ abs(i) < abs(j), ∃ i0, j0. gcd(abs(i), abs(j)) = i * i0 + j * j0

Rule argument

fma: abs(i) < abs(j)

Additional information

Used formulas: abs(i) < abs(j)