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Proof step 24 from proof isSquare-mult (previous step)

j0 * j0 = j * i * i ⊦ abs(j0 * j0) = abs(j) * abs(i) * abs(i), i = 0, isSquare(j)

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: abs-eqall: ⊦ abs(i * j) = abs(i) * abs(j); from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult