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Proof step 22 from proof isSquare-mult (previous step)

j0 * j0 = j * i * i ⊦ abs(j0) * abs(j0) = abs(j) * abs(i) * abs(i), i = 0, isSquare(j)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 23:
⊦ abs(i * j) = abs(i) * abs(j)
Proof step 24:
j0 * j0 = j * i * i ⊦ abs(j0 * j0) = abs(j) * abs(i) * abs(i), i = 0, isSquare(j)

Rule argument

spec: int-mult inst: name: abs-eqall seq: ⊦ abs(i * j) = abs(i) * abs(j) subst: [j, i] → [j0, j0] flags: rewrite

Additional information

Used terms: j0, j0