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Proof step 6 from proof isSquare-mult (previous step)

j0 * j0 = j * i * i ⊦ i = 0, isSquare(j)

User applied rule cut formula

And obtained the following new goals

Proof step 7:
abs(j0) * abs(j0) = abs(j) * abs(i) * abs(i), j0 * j0 = j * i * i ⊦ i = 0, isSquare(j)
Proof step 22:
j0 * j0 = j * i * i ⊦ abs(j0) * abs(j0) = abs(j) * abs(i) * abs(i), i = 0, isSquare(j)

Rule argument

fma: abs(j0) * abs(j0) = abs(j) * abs(i) * abs(i)

Additional information

Used formulas: abs(j0) * abs(j0) = abs(j) * abs(i) * abs(i)