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Proof step 14 from proof max_prime_divisor-ge2 (previous step)

max_prime_divisor(i) * i0 = i, i0 ≤ 0, i0 < i, 0 < i, 0 ≤ i, 2 ≤ i ⊦ prime(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ 0 ≤ i ∧ 0 < j ∧ i1 < 0 → i * i1 ≠ j
Proof step 16:
¬(0 ≤ max_prime_divisor(i) ∧ 0 < i ∧ i0 < 0), max_prime_divisor(i) * i0 = i, i0 ≤ 0, i0 < i, 0 < i, 0 ≤ i, 2 ≤ i ⊦ prime(i)

Rule argument

spec: int-mult inst: name: mult-pos seq: ⊦ 0 ≤ i ∧ 0 < j ∧ i1 < 0 → i * i1 ≠ j subst: [j, i1, i] → [i, i0, max_prime_divisor(i)] flags: rewrite

Additional information

Used terms: i, i0, max_prime_divisor(i)