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Proof step 16 from proof max_prime_divisor-ge2 (previous step)

¬(0 ≤ max_prime_divisor(i) ∧ 0 < i ∧ i0 < 0), max_prime_divisor(i) * i0 = i, i0 ≤ 0, i0 < i, 0 < i, 0 ≤ i, 2 ≤ i ⊦ prime(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information