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Proof step 2 from proof prime-odd-01 (previous step)

prime(j) ⊦ (j - 1) % 2 = 0, j = 2

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
j = i0 + 1, prime(j) ⊦ i0 % 2 = 0, j = 2

Rule argument

spec: int-abs inst: name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [j, 1, i] flags:

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: j, 1, i