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Proof step 3 from proof prime-odd-01 (previous step)

j = i0 + 1, prime(j) ⊦ i0 % 2 = 0, j = 2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
prime(i0 + 1) ⊦ i0 % 2 = 0, 1 = i0

Rule argument

Additional information

Used simplifier rules: add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%numadd-01: ⊦ (* j) = i0 + (* j0) ↔ j - j0 = i0; from specification int-abs