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Proof step 7 from proof square-neq-any-pos-01 (previous step)

j ≠ 0, j / gcd(j, j0) * j = (i * j0 * j0) / gcd(j, j0), 0 < i, 0 < j, 0 < j0 ⊦ gcd(j, j0) = 1, ∃ i0. i = i0 * i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
j / gcd(j, j0) * j = (i * j0 * j0) / gcd(j, j0), 0 < i, 0 < j, 0 < j0 ⊦ gcd(j, j0) = 1, j = 0, ∃ i0. i = i0 * i0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs