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Proof step 8 from proof square-neq-any-pos-01 (previous step)

j / gcd(j, j0) * j = (i * j0 * j0) / gcd(j, j0), 0 < i, 0 < j, 0 < j0 ⊦ gcd(j, j0) = 1, j = 0, ∃ i0. i = i0 * i0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ i * j = j * i
Proof step 10:
j / gcd(j, j0) * j = ((j0 * j0) * i) / gcd(j, j0), 0 < i, 0 < j, 0 < j0 ⊦ gcd(j, j0) = 1, j = 0, ∃ i0. i = i0 * i0

Rule argument

spec: int-mult inst: name: commutativity seq: ⊦ i * j = j * i subst: [j, i] → [j0 * j0, i] flags: rewrite

Additional information

Used terms: j0 * j0, i