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Proof step 1 from proof square-neq-pos-h (conclusion)

⊦ prime(i) ∧ gcd(j, j0) = 1 ∧ 0 < j ∧ 0 ≤ j0 → j * j ≠ i * j0 * j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
j * j = i * j0 * j0, gcd(j, j0) = 1, prime(i), 0 < j, 0 ≤ j0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs