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Proof step 2 from proof square-neq-pos-h (previous step)

j * j = i * j0 * j0, gcd(j, j0) = 1, prime(i), 0 < j, 0 ≤ j0 ⊦

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: i | j

Additional information

Used simplifier rules: square-prime-eq: ⊦ prime(j) ∧ ¬ j | i → i * i ≠ j * j0;%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult Used formulas: i | j