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Proof step 2 from proof square-prime-eq (previous step)

i * i = j * j0, prime(j) ⊦ j | i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ gcd(i, j) = 1 ∧ ¬ i | j0 → i * i0 ≠ j * j0
Proof step 4:
¬(gcd(i, j) = 1 ∧ ¬ i | j0), i * i = j * j0, prime(j) ⊦ j | i

Rule argument

spec: inst: name: coprime-divides-04 seq: ⊦ gcd(i, j) = 1 ∧ ¬ i | j0 → i * i0 ≠ j * j0 subst: [j0, j, i0, i] → [j0, j, i, i] flags: rewrite, current

Additional information

Used terms: j0, j, i, i