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Proof step 4 from proof square-prime-eq (previous step)

¬(gcd(i, j) = 1 ∧ ¬ i | j0), i * i = j * j0, prime(j) ⊦ j | i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i * i = j * j0, prime(j), i | j0 ⊦ j | i

Rule argument

Additional information

Used simplifier rules: gcd-one-prime: ⊦ prime(i) ∧ ¬ i | j → gcd(i, j) = 1;%gcd-com: ⊦ gcd(i, j) = gcd(j, i);