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Proof step 5 from proof square-prime-eq (
previous step
)
i * i = j * j0, prime(j), i | j0 ⊦ j | i
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 6
:
⊦ i | j ↔ (∃ i0. i * i0 = j)
Proof step 7
:
i * i = j * j0, prime(j), ∃ i0. i * i0 = j0 ⊦ j | i
Rule argument
spec: inst: name: divides seq: ⊦ i | j ↔ (∃ i0. i * i0 = j) subst: [j, i] → [j0, i] flags: rewrite, current
Additional information
Used terms: j0, i