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Proof step 8 from proof max-a (previous step)

max(j, j0) ≤ i ⊦ max(i, j) < j0, i = max(max(i, j), j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
max(j, j0) ≤ i, j0 ≤ max(i, j) ⊦ i = max(i, j)

Rule argument

Additional information

Used simplifier rules: Max-left: ⊦ ¬ j < i → max(j, i) = j;%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs