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Proof step 9 from proof max-a (previous step)

max(j, j0) ≤ i, j0 ≤ max(i, j) ⊦ i = max(i, j)

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: i < j

Additional information

Used simplifier rules: Max-right: ⊦ j < i → max(j, i) = i;%max-01: ⊦ max(i, j) < j0 ↔ i < j0 ∧ j < j0;%Max-left: ⊦ ¬ j < i → max(j, i) = j;%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%irref: ⊦ ¬ i < i; from specification int-basic1 Used formulas: i < j