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Proof step 6 from proof odd-add (previous step)

⊦ (¬ even(i) ∨ ¬ even(j)) ∧ (¬ odd(i) ∨ ¬ odd(j)) ↔ odd(i) ∧ even(j) ∨ even(i) ∧ odd(j)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: inst: name: odd-even-rew seq: ⊦ odd(i) ↔ ¬ even(i) subst: [i] → [i] flags: rewrite, current

Additional information

Used terms: i