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Proof step 8 from proof odd-add (previous step)

⊦ (¬ even(i) ∨ ¬ even(j)) ∧ (¬ ¬ even(i) ∨ ¬ odd(j)) ↔ ¬ even(i) ∧ even(j) ∨ even(i) ∧ odd(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information