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Proof step 1 from proof numle-11 (conclusion)
⊦ i < 0 → ((* i) * j ≤ (* i) * j0 ↔ j0 ≤ j)
Special step normalize
And obtained the following new goals
Proof step 2
:
⊦ i < 0 → (i * j ≤ i * j0 ↔ j0 ≤ j)