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Proof step 2 from proof numle-11 (previous step)

⊦ i < 0 → (i * j ≤ i * j0 ↔ j0 ≤ j)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: le-neg: ⊦ i < 0 → (i * j ≤ i * i0 ↔ i0 ≤ j);%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;