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Proof step 13 from proof square-ls (previous step)

abs(i) * abs(i) < abs(j) * abs(j), abs(i) < abs(j), j * j ≤ i * i ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 14:
⊦ abs(i * j) = abs(i) * abs(j)
Proof step 15:
abs(i * i) < abs(j) * abs(j), abs(i) < abs(j), j * j ≤ i * i ⊦

Rule argument

spec: int-mult inst: name: abs-eqall seq: ⊦ abs(i * j) = abs(i) * abs(j) subst: [j, i] → [i, i] flags: rewrite, current

Additional information

Used terms: i, i