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Proof step 15 from proof square-ls (previous step)

abs(i * i) < abs(j) * abs(j), abs(i) < abs(j), j * j ≤ i * i ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: int-mult inst: name: abs-eqall seq: ⊦ abs(i * j) = abs(i) * abs(j) subst: [j, i] → [j, j] flags: rewrite, current

Additional information

Used simplifier rules: square-abs: ⊦ abs(i * i) = i * i;%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;%lenls: ⊦ i ≤ j → ¬ j < i; from specification int-abs Used terms: j, j