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Proof step 15 from proof equal-minus-one (previous step)

¬ j < 0, i ^ j = ~1 ⊦ i = 0, i = ~1, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
i ^ j = ~1, 0 < j ⊦ i = 0, i = ~1

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%ls-01: ⊦ i < j → ¬ j < i; from specification int-basic1%lst-01: ⊦ ¬ i < j → (i ≠ j ↔ j < i); from specification int-basic1