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Proof step 16 from proof equal-minus-one (previous step)

i ^ j = ~1, 0 < j ⊦ i = 0, i = ~1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 17:
⊦ 0 < i → j ^ i = j ^ i -1 * j
Proof step 18:
0 < j, i ^ j -1 * i = ~1, 0 < j ⊦ i = 0, i = ~1

Rule argument

spec: inst: name: Pot-pos seq: ⊦ 0 < i → j ^ i = j ^ i -1 * j subst: [i, j] → [j, i] flags: rewrite, current

Additional information

Used terms: j, i