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Proof step 1 from proof isSquare-10pot (conclusion)

⊦ isSquare(10 ^ (2 * abs(i)))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ isSquare(i) ↔ (∃ j. j * j = i)
Proof step 3:
⊦ ∃ j. j * j = 10 ^ (2 * abs(i))

Rule argument

spec: int-square inst: name: isSquare-def seq: ⊦ isSquare(i) ↔ (∃ j. j * j = i) subst: [i] → [10 ^ (2 * abs(i))] flags: rewrite

Additional information

Used terms: 10 ^ (2 * abs(i))